log(3x-2)+log(x+2)=1

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Solution for log(3x-2)+log(x+2)=1 equation:


Simplifying
log(3x + -2) + log(x + 2) = 1

Reorder the terms:
glo(-2 + 3x) + log(x + 2) = 1
(-2 * glo + 3x * glo) + log(x + 2) = 1
(-2glo + 3glox) + log(x + 2) = 1

Reorder the terms:
-2glo + 3glox + glo(2 + x) = 1
-2glo + 3glox + (2 * glo + x * glo) = 1
-2glo + 3glox + (2glo + glox) = 1

Reorder the terms:
-2glo + 2glo + 3glox + glox = 1

Combine like terms: -2glo + 2glo = 0
0 + 3glox + glox = 1
3glox + glox = 1

Combine like terms: 3glox + glox = 4glox
4glox = 1

Solving
4glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '4lox'.
g = 0.25l-1o-1x-1

Simplifying
g = 0.25l-1o-1x-1

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