log(4)(x+1)-log(4)x=2

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Solution for log(4)(x+1)-log(4)x=2 equation:


Simplifying
log(4)(x + 1) + -1log(4) * x = 2

Reorder the terms:
glo * 4(1 + x) + -1log(4) * x = 2

Reorder the terms for easier multiplication:
4glo(1 + x) + -1log(4) * x = 2
(1 * 4glo + x * 4glo) + -1log(4) * x = 2
(4glo + 4glox) + -1log(4) * x = 2

Reorder the terms for easier multiplication:
4glo + 4glox + -1 * 4glo * x = 2

Multiply -1 * 4
4glo + 4glox + -4glo * x = 2

Multiply glo * x
4glo + 4glox + -4glox = 2

Combine like terms: 4glox + -4glox = 0
4glo + 0 = 2
4glo = 2

Solving
4glo = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '4lo'.
g = 0.5l-1o-1

Simplifying
g = 0.5l-1o-1

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