log(4-5x)+(8x)=1

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Solution for log(4-5x)+(8x)=1 equation:


Simplifying
log(4 + -5x) + (8x) = 1
(4 * glo + -5x * glo) + (8x) = 1
(4glo + -5glox) + (8x) = 1

Solving
4glo + -5glox + (8x) = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '(-8x)' to each side of the equation.
4glo + -5glox + (8x) + (-8x) = 1 + (-8x)

Combine like terms: (8x) + (-8x) = 0
4glo + -5glox + 0 = 1 + (-8x)
4glo + -5glox = 1 + (-8x)

Reorder the terms:
-1 + 4glo + -5glox + (8x) = 1 + (-8x) + -1 + (8x)

Reorder the terms:
-1 + 4glo + -5glox + (8x) = 1 + -1 + (-8x) + (8x)

Combine like terms: 1 + -1 = 0
-1 + 4glo + -5glox + (8x) = 0 + (-8x) + (8x)
-1 + 4glo + -5glox + (8x) = (-8x) + (8x)

Combine like terms: (-8x) + (8x) = 0
-1 + 4glo + -5glox + (8x) = 0

The solution to this equation could not be determined.

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