log(4x+22)-log(2x+1)=1

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Solution for log(4x+22)-log(2x+1)=1 equation:


Simplifying
log(4x + 22) + -1log(2x + 1) = 1

Reorder the terms:
glo(22 + 4x) + -1log(2x + 1) = 1
(22 * glo + 4x * glo) + -1log(2x + 1) = 1
(22glo + 4glox) + -1log(2x + 1) = 1

Reorder the terms:
22glo + 4glox + -1glo(1 + 2x) = 1
22glo + 4glox + (1 * -1glo + 2x * -1glo) = 1
22glo + 4glox + (-1glo + -2glox) = 1

Reorder the terms:
22glo + -1glo + 4glox + -2glox = 1

Combine like terms: 22glo + -1glo = 21glo
21glo + 4glox + -2glox = 1

Combine like terms: 4glox + -2glox = 2glox
21glo + 2glox = 1

Solving
21glo + 2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 21glo + 2glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 21glo + 2glox = 0

The solution to this equation could not be determined.

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