log(4x-2)-log(x-2)=1

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Solution for log(4x-2)-log(x-2)=1 equation:


Simplifying
log(4x + -2) + -1log(x + -2) = 1

Reorder the terms:
glo(-2 + 4x) + -1log(x + -2) = 1
(-2 * glo + 4x * glo) + -1log(x + -2) = 1
(-2glo + 4glox) + -1log(x + -2) = 1

Reorder the terms:
-2glo + 4glox + -1glo(-2 + x) = 1
-2glo + 4glox + (-2 * -1glo + x * -1glo) = 1
-2glo + 4glox + (2glo + -1glox) = 1

Reorder the terms:
-2glo + 2glo + 4glox + -1glox = 1

Combine like terms: -2glo + 2glo = 0
0 + 4glox + -1glox = 1
4glox + -1glox = 1

Combine like terms: 4glox + -1glox = 3glox
3glox = 1

Solving
3glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '3lox'.
g = 0.3333333333l-1o-1x-1

Simplifying
g = 0.3333333333l-1o-1x-1

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