log(5+x)-log(x-1)=2

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Solution for log(5+x)-log(x-1)=2 equation:


Simplifying
log(5 + x) + -1log(x + -1) = 2
(5 * glo + x * glo) + -1log(x + -1) = 2
(5glo + glox) + -1log(x + -1) = 2

Reorder the terms:
5glo + glox + -1glo(-1 + x) = 2
5glo + glox + (-1 * -1glo + x * -1glo) = 2
5glo + glox + (1glo + -1glox) = 2

Reorder the terms:
5glo + 1glo + glox + -1glox = 2

Combine like terms: 5glo + 1glo = 6glo
6glo + glox + -1glox = 2

Combine like terms: glox + -1glox = 0
6glo + 0 = 2
6glo = 2

Solving
6glo = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '6lo'.
g = 0.3333333333l-1o-1

Simplifying
g = 0.3333333333l-1o-1

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