log(5x-2)+log(x+4)=1

Solution for log(5x-2)+log(x+4)=1 equation:

Simplifying
log(5x + -2) + log(x + 4) = 1

Reorder the terms:
glo(-2 + 5x) + log(x + 4) = 1
(-2 * glo + 5x * glo) + log(x + 4) = 1
(-2glo + 5glox) + log(x + 4) = 1

Reorder the terms:
-2glo + 5glox + glo(4 + x) = 1
-2glo + 5glox + (4 * glo + x * glo) = 1
-2glo + 5glox + (4glo + glox) = 1

Reorder the terms:
-2glo + 4glo + 5glox + glox = 1

Combine like terms: -2glo + 4glo = 2glo
2glo + 5glox + glox = 1

Combine like terms: 5glox + glox = 6glox
2glo + 6glox = 1

Solving
2glo + 6glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + 6glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + 6glox = 0

The solution to this equation could not be determined.