log(6)(5/3x)=2

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Solution for log(6)(5/3x)=2 equation: 


D( x )

(5/3)*x <= 0

(5/3)*x <= 0

(5/3)*x <= 0

5/3*x+0 <= 0 // - 0

5/3*x <= 0 // : 5/3

x <= 0/5/3

x <= 0

x in (0:+oo)

log(6)((5/3)*x) = 2 // - 2

log(6)((5/3)*x)-2 = 0

log(6)((5/3)*x)-2 = 0 // + 2

log(6)((5/3)*x) = 2

log(6)((5/3)*x) = log(6)(6^2)

(5/3)*x = 6^2

(5/3)*x-6^2 = 0

5/3*x-36 = 0 // + 36

5/3*x = 36 // : 5/3

x = 36/5/3

x = 108/5

x = 108/5

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