log(6)(x)-log(6)(x+1)=2

Solution for log(6)(x)-log(6)(x+1)=2 equation:

Simplifying
log(6)(x) + -1log(6)(x + 1) = 2

Reorder the terms for easier multiplication:
6glo * x + -1log(6)(x + 1) = 2

Multiply glo * x
6glox + -1log(6)(x + 1) = 2

Reorder the terms:
6glox + -1glo * 6(1 + x) = 2

Reorder the terms for easier multiplication:
6glox + -1 * 6glo(1 + x) = 2

Multiply -1 * 6
6glox + -6glo(1 + x) = 2
6glox + (1 * -6glo + x * -6glo) = 2
6glox + (-6glo + -6glox) = 2

Reorder the terms:
-6glo + 6glox + -6glox = 2

Combine like terms: 6glox + -6glox = 0
-6glo + 0 = 2
-6glo = 2

Solving
-6glo = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '-6lo'.
g = -0.3333333333l-1o-1

Simplifying
g = -0.3333333333l-1o-1