log(6x+2)=1+(logx-4)

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Solution for log(6x+2)=1+(logx-4) equation:


Simplifying
log(6x + 2) = 1 + (logx + -4)

Reorder the terms:
glo(2 + 6x) = 1 + (logx + -4)
(2 * glo + 6x * glo) = 1 + (logx + -4)
(2glo + 6glox) = 1 + (logx + -4)

Reorder the terms:
2glo + 6glox = 1 + (-4 + glox)

Remove parenthesis around (-4 + glox)
2glo + 6glox = 1 + -4 + glox

Combine like terms: 1 + -4 = -3
2glo + 6glox = -3 + glox

Solving
2glo + 6glox = -3 + glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1glox' to each side of the equation.
2glo + 6glox + -1glox = -3 + glox + -1glox

Combine like terms: 6glox + -1glox = 5glox
2glo + 5glox = -3 + glox + -1glox

Combine like terms: glox + -1glox = 0
2glo + 5glox = -3 + 0
2glo + 5glox = -3

Reorder the terms:
3 + 2glo + 5glox = -3 + 3

Combine like terms: -3 + 3 = 0
3 + 2glo + 5glox = 0

The solution to this equation could not be determined.

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