log(7)(70)-log(7)(35)/log(7)(5)=log(x)(y)

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Solution for log(7)(70)-log(7)(35)/log(7)(5)=log(x)(y) equation: 


D( x )

x <= 0

log(7)(5) = 0

x <= 0

log(7)(5) = 0

log(7)(5) = 0

t_1 = log(7)(5)

log(7)(5) = 0

t_1 = 0

x należy do R

x in (-oo:+oo)

x belongs to the empty set

log(7)(70)-((log(7)(35))/(log(7)(5))) = log(x)(y)

x belongs to the empty set

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