log(x)(6x+1)-log(x)-5=2

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Solution for log(x)(6x+1)-log(x)-5=2 equation: 


Simplifying
log(x)(6x + 1) + -1log(x) + -5 = 2

Reorder the terms:
glo * x(1 + 6x) + -1log(x) + -5 = 2

Multiply glo * x
glox(1 + 6x) + -1log(x) + -5 = 2
(1 * glox + 6x * glox) + -1log(x) + -5 = 2
(1glox + 6glox2) + -1log(x) + -5 = 2

Multiply glo * x
1glox + 6glox2 + -1glox + -5 = 2

Reorder the terms:
-5 + 1glox + -1glox + 6glox2 = 2

Combine like terms: 1glox + -1glox = 0
-5 + 0 + 6glox2 = 2
-5 + 6glox2 = 2

Solving
-5 + 6glox2 = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 6glox2 = 2 + 5

Combine like terms: -5 + 5 = 0
0 + 6glox2 = 2 + 5
6glox2 = 2 + 5

Combine like terms: 2 + 5 = 7
6glox2 = 7

Divide each side by '6lox2'.
g = 1.166666667l-1o-1x-2

Simplifying
g = 1.166666667l-1o-1x-2

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