log(x+1)+log(x-2)=1

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Solution for log(x+1)+log(x-2)=1 equation: 


Simplifying
log(x + 1) + log(x + -2) = 1

Reorder the terms:
glo(1 + x) + log(x + -2) = 1
(1 * glo + x * glo) + log(x + -2) = 1
(1glo + glox) + log(x + -2) = 1

Reorder the terms:
1glo + glox + glo(-2 + x) = 1
1glo + glox + (-2 * glo + x * glo) = 1
1glo + glox + (-2glo + glox) = 1

Reorder the terms:
1glo + -2glo + glox + glox = 1

Combine like terms: 1glo + -2glo = -1glo
-1glo + glox + glox = 1

Combine like terms: glox + glox = 2glox
-1glo + 2glox = 1

Solving
-1glo + 2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -1glo + 2glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -1glo + 2glox = 0

The solution to this equation could not be determined.

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