log(x+1)+log(x-4)=2

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Solution for log(x+1)+log(x-4)=2 equation:


Simplifying
log(x + 1) + log(x + -4) = 2

Reorder the terms:
glo(1 + x) + log(x + -4) = 2
(1 * glo + x * glo) + log(x + -4) = 2
(1glo + glox) + log(x + -4) = 2

Reorder the terms:
1glo + glox + glo(-4 + x) = 2
1glo + glox + (-4 * glo + x * glo) = 2
1glo + glox + (-4glo + glox) = 2

Reorder the terms:
1glo + -4glo + glox + glox = 2

Combine like terms: 1glo + -4glo = -3glo
-3glo + glox + glox = 2

Combine like terms: glox + glox = 2glox
-3glo + 2glox = 2

Solving
-3glo + 2glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -3glo + 2glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -3glo + 2glox = 0

The solution to this equation could not be determined.

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