log(x+1)-log(2x-1)=1

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Solution for log(x+1)-log(2x-1)=1 equation: 


Simplifying
log(x + 1) + -1log(2x + -1) = 1

Reorder the terms:
glo(1 + x) + -1log(2x + -1) = 1
(1 * glo + x * glo) + -1log(2x + -1) = 1
(1glo + glox) + -1log(2x + -1) = 1

Reorder the terms:
1glo + glox + -1glo(-1 + 2x) = 1
1glo + glox + (-1 * -1glo + 2x * -1glo) = 1
1glo + glox + (1glo + -2glox) = 1

Reorder the terms:
1glo + 1glo + glox + -2glox = 1

Combine like terms: 1glo + 1glo = 2glo
2glo + glox + -2glox = 1

Combine like terms: glox + -2glox = -1glox
2glo + -1glox = 1

Solving
2glo + -1glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + -1glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + -1glox = 0

The solution to this equation could not be determined.

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