log(x+1)-log(3x-2)=1

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Solution for log(x+1)-log(3x-2)=1 equation:


Simplifying
log(x + 1) + -1log(3x + -2) = 1

Reorder the terms:
glo(1 + x) + -1log(3x + -2) = 1
(1 * glo + x * glo) + -1log(3x + -2) = 1
(1glo + glox) + -1log(3x + -2) = 1

Reorder the terms:
1glo + glox + -1glo(-2 + 3x) = 1
1glo + glox + (-2 * -1glo + 3x * -1glo) = 1
1glo + glox + (2glo + -3glox) = 1

Reorder the terms:
1glo + 2glo + glox + -3glox = 1

Combine like terms: 1glo + 2glo = 3glo
3glo + glox + -3glox = 1

Combine like terms: glox + -3glox = -2glox
3glo + -2glox = 1

Solving
3glo + -2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 3glo + -2glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3glo + -2glox = 0

The solution to this equation could not be determined.

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