log(x+1)=2+log(x-1)

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Solution for log(x+1)=2+log(x-1) equation:


Simplifying
log(x + 1) = 2 + log(x + -1)

Reorder the terms:
glo(1 + x) = 2 + log(x + -1)
(1 * glo + x * glo) = 2 + log(x + -1)
(1glo + glox) = 2 + log(x + -1)

Reorder the terms:
1glo + glox = 2 + glo(-1 + x)
1glo + glox = 2 + (-1 * glo + x * glo)
1glo + glox = 2 + (-1glo + glox)

Add '-1glox' to each side of the equation.
1glo + glox + -1glox = 2 + -1glo + glox + -1glox

Combine like terms: glox + -1glox = 0
1glo + 0 = 2 + -1glo + glox + -1glox
1glo = 2 + -1glo + glox + -1glox

Combine like terms: glox + -1glox = 0
1glo = 2 + -1glo + 0
1glo = 2 + -1glo

Solving
1glo = 2 + -1glo

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add 'glo' to each side of the equation.
1glo + glo = 2 + -1glo + glo

Combine like terms: 1glo + glo = 2glo
2glo = 2 + -1glo + glo

Combine like terms: -1glo + glo = 0
2glo = 2 + 0
2glo = 2

Divide each side by '2lo'.
g = l-1o-1

Simplifying
g = l-1o-1

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