log(x+15)-log(x-1)=2

Solution for log(x+15)-log(x-1)=2 equation:

Simplifying
log(x + 15) + -1log(x + -1) = 2

Reorder the terms:
glo(15 + x) + -1log(x + -1) = 2
(15 * glo + x * glo) + -1log(x + -1) = 2
(15glo + glox) + -1log(x + -1) = 2

Reorder the terms:
15glo + glox + -1glo(-1 + x) = 2
15glo + glox + (-1 * -1glo + x * -1glo) = 2
15glo + glox + (1glo + -1glox) = 2

Reorder the terms:
15glo + 1glo + glox + -1glox = 2

Combine like terms: 15glo + 1glo = 16glo
16glo + glox + -1glox = 2

Combine like terms: glox + -1glox = 0
16glo + 0 = 2
16glo = 2

Solving
16glo = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '16lo'.
g = 0.125l-1o-1

Simplifying
g = 0.125l-1o-1