log(x+2)+log(x-2)=1

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Solution for log(x+2)+log(x-2)=1 equation: 


Simplifying
log(x + 2) + log(x + -2) = 1

Reorder the terms:
glo(2 + x) + log(x + -2) = 1
(2 * glo + x * glo) + log(x + -2) = 1
(2glo + glox) + log(x + -2) = 1

Reorder the terms:
2glo + glox + glo(-2 + x) = 1
2glo + glox + (-2 * glo + x * glo) = 1
2glo + glox + (-2glo + glox) = 1

Reorder the terms:
2glo + -2glo + glox + glox = 1

Combine like terms: 2glo + -2glo = 0
0 + glox + glox = 1
glox + glox = 1

Combine like terms: glox + glox = 2glox
2glox = 1

Solving
2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '2lox'.
g = 0.5l-1o-1x-1

Simplifying
g = 0.5l-1o-1x-1

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