log(x+2)-log(x+1)=1

Solution for log(x+2)-log(x+1)=1 equation:

Simplifying
log(x + 2) + -1log(x + 1) = 1

Reorder the terms:
glo(2 + x) + -1log(x + 1) = 1
(2 * glo + x * glo) + -1log(x + 1) = 1
(2glo + glox) + -1log(x + 1) = 1

Reorder the terms:
2glo + glox + -1glo(1 + x) = 1
2glo + glox + (1 * -1glo + x * -1glo) = 1
2glo + glox + (-1glo + -1glox) = 1

Reorder the terms:
2glo + -1glo + glox + -1glox = 1

Combine like terms: 2glo + -1glo = 1glo
1glo + glox + -1glox = 1

Combine like terms: glox + -1glox = 0
1glo + 0 = 1
1glo = 1

Solving
1glo = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '1lo'.
g = l-1o-1

Simplifying
g = l-1o-1