log(x+2)=1+(4x-3)

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Solution for log(x+2)=1+(4x-3) equation:


Simplifying
log(x + 2) = 1 + (4x + -3)

Reorder the terms:
glo(2 + x) = 1 + (4x + -3)
(2 * glo + x * glo) = 1 + (4x + -3)
(2glo + glox) = 1 + (4x + -3)

Reorder the terms:
2glo + glox = 1 + (-3 + 4x)

Remove parenthesis around (-3 + 4x)
2glo + glox = 1 + -3 + 4x

Combine like terms: 1 + -3 = -2
2glo + glox = -2 + 4x

Solving
2glo + glox = -2 + 4x

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
2 + 2glo + glox + -4x = -2 + 4x + 2 + -4x

Reorder the terms:
2 + 2glo + glox + -4x = -2 + 2 + 4x + -4x

Combine like terms: -2 + 2 = 0
2 + 2glo + glox + -4x = 0 + 4x + -4x
2 + 2glo + glox + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
2 + 2glo + glox + -4x = 0

The solution to this equation could not be determined.

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