log(x+2)=8-ln(2x+1)

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Solution for log(x+2)=8-ln(2x+1) equation:


Simplifying
log(x + 2) = 8 + -1ln(2x + 1)

Reorder the terms:
glo(2 + x) = 8 + -1ln(2x + 1)
(2 * glo + x * glo) = 8 + -1ln(2x + 1)
(2glo + glox) = 8 + -1ln(2x + 1)

Reorder the terms:
2glo + glox = 8 + -1ln(1 + 2x)
2glo + glox = 8 + (1 * -1ln + 2x * -1ln)
2glo + glox = 8 + (-1ln + -2lnx)

Solving
2glo + glox = 8 + -1ln + -2lnx

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-8 + 2glo + glox + ln + 2lnx = 8 + -1ln + -2lnx + -8 + ln + 2lnx

Reorder the terms:
-8 + 2glo + glox + ln + 2lnx = 8 + -8 + -1ln + ln + -2lnx + 2lnx

Combine like terms: 8 + -8 = 0
-8 + 2glo + glox + ln + 2lnx = 0 + -1ln + ln + -2lnx + 2lnx
-8 + 2glo + glox + ln + 2lnx = -1ln + ln + -2lnx + 2lnx

Combine like terms: -1ln + ln = 0
-8 + 2glo + glox + ln + 2lnx = 0 + -2lnx + 2lnx
-8 + 2glo + glox + ln + 2lnx = -2lnx + 2lnx

Combine like terms: -2lnx + 2lnx = 0
-8 + 2glo + glox + ln + 2lnx = 0

The solution to this equation could not be determined.

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