log(x+3)+log(x-3)=2

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Solution for log(x+3)+log(x-3)=2 equation:


Simplifying
log(x + 3) + log(x + -3) = 2

Reorder the terms:
glo(3 + x) + log(x + -3) = 2
(3 * glo + x * glo) + log(x + -3) = 2
(3glo + glox) + log(x + -3) = 2

Reorder the terms:
3glo + glox + glo(-3 + x) = 2
3glo + glox + (-3 * glo + x * glo) = 2
3glo + glox + (-3glo + glox) = 2

Reorder the terms:
3glo + -3glo + glox + glox = 2

Combine like terms: 3glo + -3glo = 0
0 + glox + glox = 2
glox + glox = 2

Combine like terms: glox + glox = 2glox
2glox = 2

Solving
2glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '2lox'.
g = l-1o-1x-1

Simplifying
g = l-1o-1x-1

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