log(x+3)-log(4x+2)=12

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Solution for log(x+3)-log(4x+2)=12 equation:


Simplifying
log(x + 3) + -1log(4x + 2) = 12

Reorder the terms:
glo(3 + x) + -1log(4x + 2) = 12
(3 * glo + x * glo) + -1log(4x + 2) = 12
(3glo + glox) + -1log(4x + 2) = 12

Reorder the terms:
3glo + glox + -1glo(2 + 4x) = 12
3glo + glox + (2 * -1glo + 4x * -1glo) = 12
3glo + glox + (-2glo + -4glox) = 12

Reorder the terms:
3glo + -2glo + glox + -4glox = 12

Combine like terms: 3glo + -2glo = 1glo
1glo + glox + -4glox = 12

Combine like terms: glox + -4glox = -3glox
1glo + -3glox = 12

Solving
1glo + -3glox = 12

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-12 + 1glo + -3glox = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 1glo + -3glox = 0

The solution to this equation could not be determined.

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