log(x+4)+log(x-4)=2

Solution for log(x+4)+log(x-4)=2 equation:

Simplifying
log(x + 4) + log(x + -4) = 2

Reorder the terms:
glo(4 + x) + log(x + -4) = 2
(4 * glo + x * glo) + log(x + -4) = 2
(4glo + glox) + log(x + -4) = 2

Reorder the terms:
4glo + glox + glo(-4 + x) = 2
4glo + glox + (-4 * glo + x * glo) = 2
4glo + glox + (-4glo + glox) = 2

Reorder the terms:
4glo + -4glo + glox + glox = 2

Combine like terms: 4glo + -4glo = 0
0 + glox + glox = 2
glox + glox = 2

Combine like terms: glox + glox = 2glox
2glox = 2

Solving
2glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '2lox'.
g = l-1o-1x-1

Simplifying
g = l-1o-1x-1