log(x-1)-log(x+2)=1

Solution for log(x-1)-log(x+2)=1 equation:

Simplifying
log(x + -1) + -1log(x + 2) = 1

Reorder the terms:
glo(-1 + x) + -1log(x + 2) = 1
(-1 * glo + x * glo) + -1log(x + 2) = 1
(-1glo + glox) + -1log(x + 2) = 1

Reorder the terms:
-1glo + glox + -1glo(2 + x) = 1
-1glo + glox + (2 * -1glo + x * -1glo) = 1
-1glo + glox + (-2glo + -1glox) = 1

Reorder the terms:
-1glo + -2glo + glox + -1glox = 1

Combine like terms: -1glo + -2glo = -3glo
-3glo + glox + -1glox = 1

Combine like terms: glox + -1glox = 0
-3glo + 0 = 1
-3glo = 1

Solving
-3glo = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '-3lo'.
g = -0.3333333333l-1o-1

Simplifying
g = -0.3333333333l-1o-1