log(x-2)+log(x+2)=1

Solution for log(x-2)+log(x+2)=1 equation:

Simplifying
log(x + -2) + log(x + 2) = 1

Reorder the terms:
glo(-2 + x) + log(x + 2) = 1
(-2 * glo + x * glo) + log(x + 2) = 1
(-2glo + glox) + log(x + 2) = 1

Reorder the terms:
-2glo + glox + glo(2 + x) = 1
-2glo + glox + (2 * glo + x * glo) = 1
-2glo + glox + (2glo + glox) = 1

Reorder the terms:
-2glo + 2glo + glox + glox = 1

Combine like terms: -2glo + 2glo = 0
0 + glox + glox = 1
glox + glox = 1

Combine like terms: glox + glox = 2glox
2glox = 1

Solving
2glox = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '2lox'.
g = 0.5l-1o-1x-1

Simplifying
g = 0.5l-1o-1x-1