logx(1/8)=-3

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Solution for logx(1/8)=-3 equation: 


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((2*t^6)/(s^-4))*u^-5 = 0

k/4-8 = 1

1 = x-(5/4)

e^-2*x*cos(3.14*x)

(4*x)/3-2 = 14

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