logx(7y+1)-logx(2y)=1

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Solution for logx(7y+1)-logx(2y)=1 equation:


Simplifying
logx(7y + 1) + -1logx(2y) = 1

Reorder the terms:
glox(1 + 7y) + -1logx(2y) = 1
(1 * glox + 7y * glox) + -1logx(2y) = 1
(1glox + 7gloxy) + -1logx(2y) = 1

Remove parenthesis around (2y)
1glox + 7gloxy + -1glox * 2y = 1

Reorder the terms for easier multiplication:
1glox + 7gloxy + -1 * 2glox * y = 1

Multiply -1 * 2
1glox + 7gloxy + -2glox * y = 1

Multiply glox * y
1glox + 7gloxy + -2gloxy = 1

Combine like terms: 7gloxy + -2gloxy = 5gloxy
1glox + 5gloxy = 1

Solving
1glox + 5gloxy = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 1glox + 5gloxy = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1glox + 5gloxy = 0

The solution to this equation could not be determined.

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