logx+1(4x-15)=2

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Solution for logx+1(4x-15)=2 equation:


Simplifying
logx + 1(4x + -15) = 2

Reorder the terms:
glox + 1(-15 + 4x) = 2
glox + (-15 * 1 + 4x * 1) = 2
glox + (-15 + 4x) = 2

Reorder the terms:
-15 + glox + 4x = 2

Solving
-15 + glox + 4x = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + glox + 15 + 4x = 2 + 15

Reorder the terms:
-15 + 15 + glox + 4x = 2 + 15

Combine like terms: -15 + 15 = 0
0 + glox + 4x = 2 + 15
glox + 4x = 2 + 15

Combine like terms: 2 + 15 = 17
glox + 4x = 17

Add '-4x' to each side of the equation.
glox + 4x + -4x = 17 + -4x

Combine like terms: 4x + -4x = 0
glox + 0 = 17 + -4x
glox = 17 + -4x

Divide each side by 'lox'.
g = 17l-1o-1x-1 + -4l-1o-1

Simplifying
g = 17l-1o-1x-1 + -4l-1o-1

Reorder the terms:
g = -4l-1o-1 + 17l-1o-1x-1

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