m(3-4m)=7+(8-m2)

Solution for m(3-4m)=7+(8-m2) equation:

m(3-4m)=7+(8-m2)

We move all terms to the left:

m(3-4m)-(7+(8-m2))=0

We add all the numbers together, and all the variables

-(7+(-1m^2+8))+m(-4m+3)=0

We multiply parentheses

-(7+(-1m^2+8))-4m^2+3m=0


We calculate terms in parentheses: -(7+(-1m^2+8)), so:

7+(-1m^2+8)

determiningTheFunctionDomain
(-1m^2+8)+7

We get rid of parentheses

-1m^2+8+7

We add all the numbers together, and all the variables

-1m^2+15

Back to the equation:

-(-1m^2+15)


We add all the numbers together, and all the variables

-4m^2-(-1m^2+15)+3m=0

We get rid of parentheses

-4m^2+1m^2+3m-15=0

We add all the numbers together, and all the variables

-3m^2+3m-15=0

a = -3; b = 3; c = -15;
Δ = b2-4ac
Δ = 32-4·(-3)·(-15)
Δ = -171
Delta is less than zero, so there is no solution for the equation