m(3-4m)=7+498-m2

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Solution for m(3-4m)=7+498-m2 equation:



m(3-4m)=7+498-m2
We move all terms to the left:
m(3-4m)-(7+498-m2)=0
We add all the numbers together, and all the variables
-(-1m^2+7+498)+m(-4m+3)=0
We multiply parentheses
-(-1m^2+7+498)-4m^2+3m=0
We get rid of parentheses
1m^2-4m^2+3m-7-498=0
We add all the numbers together, and all the variables
-3m^2+3m-505=0
a = -3; b = 3; c = -505;
Δ = b2-4ac
Δ = 32-4·(-3)·(-505)
Δ = -6051
Delta is less than zero, so there is no solution for the equation

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