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m(3/7)=77
We move all terms to the left:
m(3/7)-(77)=0
We add all the numbers together, and all the variables
m(+3/7)-77=0
We multiply parentheses
3m^2-77=0
a = 3; b = 0; c = -77;
Δ = b2-4ac
Δ = 02-4·3·(-77)
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{231}}{2*3}=\frac{0-2\sqrt{231}}{6} =-\frac{2\sqrt{231}}{6} =-\frac{\sqrt{231}}{3} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{231}}{2*3}=\frac{0+2\sqrt{231}}{6} =\frac{2\sqrt{231}}{6} =\frac{\sqrt{231}}{3} $
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