m(m+23)=-132

Solution for m(m+23)=-132 equation:

m(m+23)=-132

We move all terms to the left:

m(m+23)-(-132)=0

We add all the numbers together, and all the variables

m(m+23)+132=0

We multiply parentheses

m^2+23m+132=0

a = 1; b = 23; c = +132;
Δ = b2-4ac
Δ = 232-4·1·132
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-1}{2*1}=\frac{-24}{2}
=-12
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+1}{2*1}=\frac{-22}{2}
=-11
$