m(m-3=54)

Solution for m(m-3=54) equation:

m(m-3=54)

We move all terms to the left:

m(m-3-(54))=0

We add all the numbers together, and all the variables

m(m-57)=0

We multiply parentheses

m^2-57m=0

a = 1; b = -57; c = 0;
Δ = b2-4ac
Δ = -572-4·1·0
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-57}{2*1}=\frac{0}{2}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+57}{2*1}=\frac{114}{2}
=57
$