m(m-4)+2(m+1)=0

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Solution for m(m-4)+2(m+1)=0 equation: 



m(m-4)+2(m+1)=0

We multiply parentheses

m^2-4m+2m+2=0

We add all the numbers together, and all the variables

m^2-2m+2=0

a = 1; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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