m(n+n)+n(2m+3n)=

Solution for m(n+n)+n(2m+3n)= equation:

Simplifying
m(n + n) + n(2m + 3n) = 0

Combine like terms: n + n = 2n
m(2n) + n(2m + 3n) = 0

Remove parenthesis around (2n)
m * 2n + n(2m + 3n) = 0

Reorder the terms for easier multiplication:
2m * n + n(2m + 3n) = 0

Multiply m * n
2mn + n(2m + 3n) = 0
2mn + (2m * n + 3n * n) = 0
2mn + (2mn + 3n2) = 0

Combine like terms: 2mn + 2mn = 4mn
4mn + 3n2 = 0

Solving
4mn + 3n2 = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-3n2' to each side of the equation.
4mn + 3n2 + -3n2 = 0 + -3n2

Combine like terms: 3n2 + -3n2 = 0
4mn + 0 = 0 + -3n2
4mn = 0 + -3n2
Remove the zero:
4mn = -3n2

Divide each side by '4n'.
m = -0.75n

Simplifying
m = -0.75n