m+(f+3)/2=40

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Solution for m+(f+3)/2=40 equation: 


x in (-oo:+oo)

(f+3)/2+m = 40 // - 40

(f+3)/2+m-40 = 0

(f+3)/2+(2*m)/2+(-40*2)/2 = 0

f+2*m-40*2+3 = 0

f+2*m-80+3 = 0

f+2*m-77 = 0

(f+2*m-77)/2 = 0

(f+2*m-77)/2 = 0 // * 2

f+2*m-77 = 0

x belongs to the empty set

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