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m+10=7/m+9
We move all terms to the left:
m+10-(7/m+9)=0
Domain of the equation: m+9)!=0We get rid of parentheses
m∈R
m-7/m-9+10=0
We multiply all the terms by the denominator
m*m-9*m+10*m-7=0
We add all the numbers together, and all the variables
m+m*m-7=0
Wy multiply elements
m^2+m-7=0
a = 1; b = 1; c = -7;
Δ = b2-4ac
Δ = 12-4·1·(-7)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{29}}{2*1}=\frac{-1-\sqrt{29}}{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{29}}{2*1}=\frac{-1+\sqrt{29}}{2} $
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