m+2m+3+3=3(m+2)

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Solution for m+2m+3+3=3(m+2) equation:



m+2m+3+3=3(m+2)
We move all terms to the left:
m+2m+3+3-(3(m+2))=0
We add all the numbers together, and all the variables
3m-(3(m+2))+6=0
We calculate terms in parentheses: -(3(m+2)), so:
3(m+2)
We multiply parentheses
3m+6
Back to the equation:
-(3m+6)
We get rid of parentheses
3m-3m-6+6=0
We add all the numbers together, and all the variables
=0
m=0/1
m=0

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