m+2m+6=(-12)+2m

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Solution for m+2m+6=(-12)+2m equation: 



m+2m+6=(-12)+2m

We move all terms to the left:

m+2m+6-((-12)+2m)=0

We add all the numbers together, and all the variables

3m-((-12)+2m)+6=0



We calculate terms in parentheses: -((-12)+2m), so:

(-12)+2m

determiningTheFunctionDomain
2m+(-12)

We add all the numbers together, and all the variables

2m-12

Back to the equation:

-(2m-12)



We get rid of parentheses

3m-2m+12+6=0

We add all the numbers together, and all the variables

m+18=0

We move all terms containing m to the left, all other terms to the right

m=-18

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