m+3/4m=14

Solution for m+3/4m=14 equation:

m+3/4m=14

We move all terms to the left:

m+3/4m-(14)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We multiply all the terms by the denominator


m*4m-14*4m+3=0

Wy multiply elements

4m^2-56m+3=0

a = 4; b = -56; c = +3;
Δ = b2-4ac
Δ = -562-4·4·3
Δ = 3088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3088}=\sqrt{16*193}=\sqrt{16}*\sqrt{193}=4\sqrt{193}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{193}}{2*4}=\frac{56-4\sqrt{193}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{193}}{2*4}=\frac{56+4\sqrt{193}}{8}
$