m+8/m=5/2

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Solution for m+8/m=5/2 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

m+8/m = 5/2 // - 5/2

m+8/m-(5/2) = 0

m+8/m-5/2 = 0

1*m^1+8*m^-1-5/2*m^0 = 0

(1*m^2-5/2*m^1+8*m^0)/(m^1) = 0 // * m^2

m^1*(1*m^2-5/2*m^1+8*m^0) = 0

m^1

m^2+(-5/2)*m+8 = 0

m^2+(-5/2)*m+8 = 0

DELTA = (-5/2)^2-(1*4*8)

DELTA = -103/4

DELTA < 0

m in { } 

m belongs to the empty set

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