m+m+m+2-8=4(m+1)-m-10

Solution for m+m+m+2-8=4(m+1)-m-10 equation:

Simplifying
m + m + m + 2 + -8 = 4(m + 1) + -1m + -10

Reorder the terms:
2 + -8 + m + m + m = 4(m + 1) + -1m + -10

Combine like terms: 2 + -8 = -6
-6 + m + m + m = 4(m + 1) + -1m + -10

Combine like terms: m + m = 2m
-6 + 2m + m = 4(m + 1) + -1m + -10

Combine like terms: 2m + m = 3m
-6 + 3m = 4(m + 1) + -1m + -10

Reorder the terms:
-6 + 3m = 4(1 + m) + -1m + -10
-6 + 3m = (1 * 4 + m * 4) + -1m + -10
-6 + 3m = (4 + 4m) + -1m + -10

Reorder the terms:
-6 + 3m = 4 + -10 + 4m + -1m

Combine like terms: 4 + -10 = -6
-6 + 3m = -6 + 4m + -1m

Combine like terms: 4m + -1m = 3m
-6 + 3m = -6 + 3m

Add '6' to each side of the equation.
-6 + 6 + 3m = -6 + 6 + 3m

Combine like terms: -6 + 6 = 0
0 + 3m = -6 + 6 + 3m
3m = -6 + 6 + 3m

Combine like terms: -6 + 6 = 0
3m = 0 + 3m
3m = 3m

Add '-3m' to each side of the equation.
3m + -3m = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.