m+m2m=(2m+4)-6

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Solution for m+m2m=(2m+4)-6 equation: 



m+m2m=(2m+4)-6

We move all terms to the left:

m+m2m-((2m+4)-6)=0



We calculate terms in parentheses: -((2m+4)-6), so:

(2m+4)-6

We get rid of parentheses

2m+4-6

We add all the numbers together, and all the variables

2m-2

Back to the equation:

-(2m-2)



We get rid of parentheses

m+m2m-2m+2=0

We add all the numbers together, and all the variables

-1m+m2m+2=0

We move all terms containing m to the left, all other terms to the right

-1m+m2m=-2

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