m-1/m+1+m/m-1=7/3

Solution for m-1/m+1+m/m-1=7/3 equation:

D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

m-(1/m)+m/m-1+1 = 7/3 // - 7/3

m-(1/m)+m/m-(7/3)-1+1 = 0

m-m^-1+m/m-7/3-1+1 = 0

1*m^1-1*m^-1-4/3*m^0 = 0

(1*m^2-4/3*m^1-1*m^0)/(m^1) = 0 // * m^2

m^1*(1*m^2-4/3*m^1-1*m^0) = 0

m^1

m^2+(-4/3)*m-1 = 0

m^2+(-4/3)*m-1 = 0

DELTA = (-4/3)^2-(-1*1*4)

DELTA = 52/9

DELTA > 0

m = ((52/9)^(1/2)-(-4/3))/(1*2) or m = (-(-4/3)-(52/9)^(1/2))/(1*2)

m = ((52/9)^(1/2)+4/3)/2 or m = (4/3-(52/9)^(1/2))/2

m in { (4/3-(52/9)^(1/2))/2, ((52/9)^(1/2)+4/3)/2} 

m in { (4/3-(52/9)^(1/2))/2, ((52/9)^(1/2)+4/3)/2 }