m-2m(2)=m(2-2m)-4

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Solution for m-2m(2)=m(2-2m)-4 equation: 



m-2m(2)=m(2-2m)-4

We move all terms to the left:

m-2m(2)-(m(2-2m)-4)=0

We add all the numbers together, and all the variables

m-2m2-(m(-2m+2)-4)=0

We add all the numbers together, and all the variables

-2m^2+m-(m(-2m+2)-4)=0



We calculate terms in parentheses: -(m(-2m+2)-4), so:

m(-2m+2)-4

We multiply parentheses

-2m^2+2m-4

Back to the equation:

-(-2m^2+2m-4)



We get rid of parentheses

-2m^2+2m^2-2m+m+4=0

We add all the numbers together, and all the variables

-1m+4=0

We move all terms containing m to the left, all other terms to the right

-m=-4

m=-4/-1

m=+4

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