m-2m=m(2-2m)

Solution for m-2m=m(2-2m) equation:

m-2m=m(2-2m)

We move all terms to the left:

m-2m-(m(2-2m))=0

We add all the numbers together, and all the variables

m-2m-(m(-2m+2))=0

We add all the numbers together, and all the variables

-1m-(m(-2m+2))=0


We calculate terms in parentheses: -(m(-2m+2)), so:

m(-2m+2)

We multiply parentheses

-2m^2+2m

Back to the equation:

-(-2m^2+2m)


We get rid of parentheses

2m^2-2m-1m=0

We add all the numbers together, and all the variables

2m^2-3m=0

a = 2; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·2·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*2}=\frac{0}{4}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*2}=\frac{6}{4}
=1+1/2
$