m-3/m+2/3-m/m+2=0

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Solution for m-3/m+2/3-m/m+2=0 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

m-(3/m)-(m/m)+2/3+2 = 0

m-3*m^-1+2/3-1+2 = 0

1*m^1-3*m^-1+5/3*m^0 = 0

(1*m^2+5/3*m^1-3*m^0)/(m^1) = 0 // * m^2

m^1*(1*m^2+5/3*m^1-3*m^0) = 0

m^1

m^2+(5/3)*m-3 = 0

m^2+(5/3)*m-3 = 0

DELTA = (5/3)^2-(-3*1*4)

DELTA = 133/9

DELTA > 0

m = ((133/9)^(1/2)-(5/3))/(1*2) or m = (-(5/3)-(133/9)^(1/2))/(1*2)

m = ((133/9)^(1/2)-5/3)/2 or m = (-((133/9)^(1/2)+5/3))/2

m in { (-((133/9)^(1/2)+5/3))/2, ((133/9)^(1/2)-5/3)/2} 

m in { (-((133/9)^(1/2)+5/3))/2, ((133/9)^(1/2)-5/3)/2 }

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