m-3=(4/5m)-2

Solution for m-3=(4/5m)-2 equation:

m-3=(4/5m)-2

We move all terms to the left:

m-3-((4/5m)-2)=0


Domain of the equation: 5m)-2)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

m-((+4/5m)-2)-3=0

We multiply all the terms by the denominator


m*5m)-2)-((-3*5m)-2)+4=0

Wy multiply elements

5m^2-15m=0

a = 5; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·5·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*5}=\frac{0}{10}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*5}=\frac{30}{10}
=3
$